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- inCAD Library Home
- > No.000035 Cylinder Linear Motion Mechanism
No.000035 Cylinder Linear Motion Mechanism
117
Table slide with stroke end adjustment
Relevant category
Shock Absorber
| Product name | Shock Absorbers |
|---|---|
| Part number | MAKC0805B |
Selection criteria
To smooth out shock and absorb energy at end stroke.
Available sizes
■Shock Absorbers (Fixed)
| Type | Thread Dia. - Pitch | Stroke | Body material | Surface treatment | Speed | Overall length | |
|---|---|---|---|---|---|---|---|
| With Cap | Without Cap | ||||||
| With Cap Without Cap | M4-0.5 | 4 | 303 Stainless Steel | - | Low Speed | 32.6 | 28.6 |
| M6-0.75 | Low Speed | 33 | 29 | ||||
| M8-0.75 | 5 | C36000 Brass | Electroless Nickel Plating | Low Speed | 37 | 32 | |
| M10-1 | Carbon Steel | Low Speed | 39 | ||||
| 8 | Low Speed | 53 | 46 | ||||
| Low Speed | 55 | 48 | |||||
| Medium Speed | |||||||
| High Speed | |||||||
Selection steps
■Shock Absorbers Selection Steps
1. Calculate the inertia energy (E1)
Calculate the energy based on the collision material mass (m), collision velocity (V), moment of inertia (I), and collision angle velocity (u), according to the selection calculation example.
↓
2. Temporarily select the absorber stroke
Determine the temporary stroke (S') according to Fig.1.
↓
3. Calculate the addition energy (E2')
Verify the existence of thrust force (F) and calculate the addition energy according to the selection calculation example.
↓
4. Calculate the total energy
Calculate the total energy by adding inertia energy (E1) and addition energy (E2') together.
↓
Fig.1 Determine the temporary stroke (S') based on the inertia energy (E1) (adjustable / fixed type)
5. Check the equivalent mass
Calculate the equivalent mass according to the selection calculation example to check if it is less than or equal to the maximum equivalent mass (me') shown in the catalog.
↓
6. Select the absorption property structure from the energy ratio.
Temporarily select the orifice type according to Fig.2.
↓
7. Check the max. absorption energy per minute
Calculate the energy per minute (ET) based on the operating cycle (times/min) and the total energy to confirm that it is within the operating range.
Fig.2 Select the orifice type based on the energy ratio (addition energy (E2') / inertia energy (E1))
Performance info.
■Shock Absorber Properties (Fixed)
| Thread Dia. - Pitch | Stroke | Speed | Max. Absorption Energy | Max. Equivalent Mass(kg) | |
|---|---|---|---|---|---|
| Each Time(J) | Per Minute(J) | ||||
| M4-0.5 | 4 | A | 0.1 | 4.5 | 1 |
| B | 0.3 | 13.5 | 3 | ||
| M6-0.75 | A | 0.1 | 4.5 | 1 | |
| B | 0.3 | 13.5 | 2 | ||
| L | 0.5 | 22.5 | 3 | ||
| M8-0.75 | 5 | A | 0.39 | 17.6 | |
| B | 0.68 | 22.5 | 5 | ||
| M10-1 | A | 41.1 | |||
| B | 0.98 | 8 | |||
| 8 | A | 58.8 | 7 | ||
| B | 1.47 | 10 | |||
| L | 2.94 | 20 | |||
| M | 9 | ||||
| H | 2.5 | ||||
| Speed Type | Impact Speed Range | |
|---|---|---|
| Low Speed | A | 0.3-1m/s |
| B | ||
| L | ||
| Medium Speed | M | 0.3-2m/s |
| High Speed | H | 0.3-3m/s |
Technical calculations
- ■Shock Absorber Energy Calculations
- Selection example: Horizontal collision with air cylinder thrust
-
- m＝30kg
- V＝0.6m/s
- N = 20 times/min
- Air Cylinder
- I.D.: φ40, Operating pressure: 0.5 Mpa
-
●Inertia energy E1 (J)
-
●Temporary stroke S' (mm)
S' = 15 mm according to Fig.1
(See the shock absorber selection steps for Fig.1) -
●Addition energy E2' (J)
Cylinder thrust is F = 628.4 N
E2' = F x S' = 628.4 x 0.015 = 9.4 J -
●Total energy E' (J)
E' = E1 + E2' = 5.4 + 9.4 = 14.8J
-
Equivalent mass me' (kg)
-
Temporary selection
Select the adjustable type
Select the medium speed M from the collision velocity
Select MAC2016M from E' and me' (stroke S = 16 mm) -
Re-calculate
E2＝F×S＝10.1J
E＝E1＋E2＝15.5J
Energy per minute ET
ET＝E×N＝15.5J×20＝310J/min
Adjusting Stopper Screw
| Product name | Adjusting Stopper Screws- Hexagon Socket, L Configurable, Fine Thread |
|---|---|
| Part number | ANB6-30 |
Selection criteria
Forward End Position Fine Adjustment
Risk info.
Contact Surface Abrasion
Available sizes
■Adjusting Stopper Screws (Hexagon Socket Type, L selectable) Spherical Tip
| Screw Type | Material | Hardness (Tip) | Surface treatment | Accessory(Nut x 1 pc.) | |
|---|---|---|---|---|---|
| Material | Surface treatment | ||||
| Fine Thread ・ Coarse Thread | 1045 Carbon Steel | 45〜50HRC | Electroless Nickel Plating | 1018 Carbon Steel | Trivalent Chromate |
| Trivalent Chromate | |||||
| 4137 Alloy Steel | 50HRC〜 | ||||
| 304 Stainless Steel | − | − | 304 Stainless Steel | − | |
| 420 Stainless Steel | 45HRC〜 | − | |||
■Size Specification
| Thread Diameter x Pitch | Overall length (in the increment of 5mm) | |
|---|---|---|
| Fine Thread | Coarse Thread | |
| M3×0.35 | M3×0.5 | 10～40 |
| M4×0.5 | M4×0.7 | 10～60 |
| M5×0.5 | M5×0.8 | 10～60 |
| M6×0.75 | M6×1.0 | 15～60 |
| M8×0.75 | M8×1.25 | 20～60 |
| M10×1.0 | M10×1.5 | 25～100 |
| M12×1.0 | M12×1.75 | 30～100 |
| M16×1.5 | M16×2.0 | 40～100 |
| M20×1.5 | M20×2.5 | 45～120 |
* Selectable size will differ depending on materials.
* For details, please see products page.
Floating Joint
| Product name | Floating Joints - Quick Connection Type - Cylinder Connector and Holder Set |
|---|---|
| Part number | FJRHA5-0.8 |
Selection criteria
A more rigid type was selected to support the load applied to cylinder.
Available sizes
■Floating Joints - Quick Connection Type
| Part No. | Part name | Material |
|---|---|---|
| ① | Stud | 304 Stainless Steel |
| ② | Nut | 1018 Carbon Steel |
| ③ | Case | C36000 Brass |
| ④ | Ball Holder | |
| ⑤ | Ball Joiner | |
| ⑥ | Socket | |
| ⑦ | Rod Tip Nut | SWCH8R Carbon Wire Steel (JIS) |
| Screw Diameter-Pitch | Stud Length | Screw Depth | Overall length |
|---|---|---|---|
| M4−0.7 | 10 | 4.5 | 26 |
| M5−0.8 | 12.5 | 6 | 33.5 |
| M6−1.0 | 15.5 | 36.5 |
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Application Overview
Purpose
- Cylinder driven table.
Target workpiece
- Small printed circuit boards.
- W40 x D110 x H1.6 mm
Design Specifications
Operating Conditions or Design Requirements
- External dims.; W120 x D564 x H45mm
- Transfer stroke: 200mm
Required Performance
- Positioning accuracy: ±0.5 /200mm
- Load: Table + Workpiece = 0.2kg
Selection Criteria for Main Components
- Select a cylinder with ample thrust for transfer.
Design Evaluation
Verification of main components
- Select cylinder bore based on work load.
- Selection of cylinder bore
- Operating conditions:
Horizontal mount
M = 0.3kg - Load mass (Workpiece, Block)
μ = 0.06 - Coefficient of friction
g = 9.8m/s² - Gravitational acceleration
P = 0.4MPa - Operating pressure
η=50 % - Load factor
Actual load F = μMg,
therefore F = 0.006 × 0.3 × 9.8 = 0.02N
Required cylinder force F0 = (F / η) × 100 ,
thus F0 = (0.02 / 50) × 100 = 0.04N
Cylinder Bore Dia. is determined based on cylinder force, F0 = A x P
Where A (mm²) - cylinder pressure area
DO=√(1.274 × F0 / P) therefore DO=√(1.274 × 0.04 / 0.4) = 3.6mm
Cylinder bore dia.: 16mm is selected
Cylinder tube I.D. DO=√(1.274 × F0 / P) therefore DO=√(1.274 × 0.04 / 0.4) = 3.6mm
Cylinder tube I.D.: 16mm is selected
- Operating conditions:
Other Design Consideration
- Shock absorbers are installed on fore/aft stroke ends to avoid impact stops.
- Stopper is located at the load center.
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